The 1/3-2/3 conjecture, in order theory, states that when comparison sorting a set of items, no matter what comparisons have already been performed, it is always possible to choose the next comparison so that it reduces the number of possible sorted orders by a factor of 2/3 or better. Equivalently, in every finite partially ordered set that is not totally ordered, there exists a pair of elements x and y such that at least 1/3 and at most 2/3 of the linear extensions of the partial order place x earlier than y. This description is adapted from Wikipedia contributors under CC BY-SA 4.0; changes were made. https://creativecommons.org/licenses/by-sa/4.0/
Facts
StatementIn every finite partially ordered set that is not totally ordered, there exists a pair of elements x and y such that at least 1/3 and at most 2/3 of the linear extensions of the partial order place x earlier than y. 1 Proposed Year Progress Toward ResolutionUnresolved. In 1995 Brightwell, Felsner and Trotter proved the bound of about 0.276 in place of 1/3, and the conjecture is verified for width two, height two and small posets. 1 Classification
Resolution Status Prize Status
Prize Status (category) Connections
In Branch
Source 1/3-2/3 conjecture (Wikipedia)
Sources
1. 1/3-2/3 Conjecture (Wikipedia)
Wikimedia FoundationLead section
the 1/3-2/3 conjecture states that, if one is comparison sorting a set of items then, no matter what comparisons may have already been performed, it is always possible to choose the next comparison in such a way that it will reduce the number of possible sorted orders by a factor of 2/3 or better
Statement section
In every finite partially ordered set that is not totally ordered, there exists a pair of elements x and y with the property that at least 1/3 and at most 2/3 of the linear extensions of the partial order place x earlier than y.
History section
The conjecture was initially formulated by Sergey Kislitsyn in 1968.
Progress on bounds section
for any finite partial order P that is not total, δ(P) ≥ 1/2 − √5/10 ≈ 0.276.
View the Source 1/3-2/3 conjecture (Wikipedia)
Reader Challenges (0)
No disputes yet. Spotted an error or a better source? Open the first one.
Sign in to dispute this or suggest a correction.