Theorem

Dilworth's Theorem

Combinatorics and Graph Theory

In any finite partially ordered set, the minimum number of chains needed to cover every element equals the maximum size of an antichain. Proved by Robert Dilworth, it is a foundational duality theorem of order theory and combinatorics, dual to Mirsky's theorem for chains and antichains reversed.

Facts
Statement
In any finite partially ordered set, the maximum size of an antichain of incomparable elements equals the minimum number of chains needed to cover all elements. 1
Proof Year
1950 1
Proof Method
Contradiction 2
Proof Method
Induction 2
Classification
Statement Form
Existence Theorem 1
Dilworth's Theorem
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Principal Result Of

Source MacTutor History of Mathematics, University of St Andrews: Robert Palmer Dilworth

Proved By

Source Dilworth's Theorem (Wikipedia)
Sources
1. Dilworth's Theorem (Wikipedia)
Wikimedia Foundation
  • lead paragraph, opening sentence
    in any finite partially ordered set, the maximum size of an antichain of incomparable elements equals the minimum number of chains needed to cover all elements
  • lead paragraph, sentence naming the publication year
    The theorem is named for the mathematician Robert P. Dilworth, who published it in 1950.
  • Lead section, statement-form reference
    A version of the theorem for infinite partially ordered sets states that, when there exists a decomposition into finitely many chains, or when there exists a finite upper bound on the size of an antichain, the sizes of the largest antichain and of the smallest chain decomposition are again equal.
  • Proved By: Robert P. Dilworth, Lead
    The theorem is named for the mathematician Robert P. Dilworth, who published it in 1950.
  • In Group: Enumerative, Additive and Algebraic Combinatorics, Lead section
    In mathematics, in the areas of order theory and combinatorics, Dilworth's theorem states that, in any finite
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2. ProofWiki: Dilworth's Theorem
ProofWiki
  • Proof section
    Aiming for a contradiction, suppose there is an $s \in S \setminus \paren {S^+ \cup S^-}$.
  • Proof section, proof method
    For the converse inequality we proceed by induction on the cardinality $\card S$ of $S$.
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MacTutor History of Mathematics, University of St Andrews: Robert Palmer Dilworth
MacTutor History of Mathematics, University of St AndrewsPrincipal Result Of: Robert P. Dilworth, Biography text
Quote, Principal Result Of: Robert P. Dilworth, Biography text
), Robert P Dilworth : The Dilworth theorems ( Boston, MA, 1990).
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