Mathematics Atlas

How Proof Is Made
Sign In
Text size
100%
Theme
Theorem

Noether Normalization Lemma

Algebra

The Noether Normalization Lemma states that for any finitely generated commutative algebra over a field, there exist algebraically independent elements of that algebra such that the whole algebra becomes a finitely generated module over the polynomial ring they generate. Named for Emmy Noether, it is a foundational structural result of commutative algebra, giving every affine variety a finite map onto an affine space and underlying much of the geometric approach to ring theory.

Facts
Statement
Let k be a field and A = k[y1', ..., ym'] be a finitely generated k-algebra. Then for some integer d, 0 <= d <= m, there exist y1, ..., yd in A algebraically independent over k such that A is finite over k[y1, ..., yd]. 1
Proof Year
1926 1
Proof Method
Induction 2
Classification
Statement Form
Existence Theorem 1
Statement Form
Inequality 1
Statement Form
Identity or Equation 1
Connections

Has Statement Form

Equation, Concepts
Identity, Concepts
Inequality, Concepts

In Branch

Source Noether normalization lemma, Wikipedia

Principal Result Of

Source Wikipedia: Emmy Noether

Proved By

Sources
1. Noether normalization lemma, Wikipedia
  • Lead section
    In mathematics, the Noether normalization lemma (sometimes referred to as a theorem rather than a lemma) is a result of commutative algebra, introduced by Emmy Noether in 1926.
  • In Branch: Commutative Algebra, Lead sentence
    as a theorem rather than a lemma) is a result of commutative algebra, introduced by Emmy Noether in 1926.
View the Source
2. ProofWiki: Noether Normalization Lemma
ProofWikiProof section
Quote, Proof section
Since $A$ is finitely generated, we prove this by induction on the number $m$ of generators as a $k$-algebra.
View the Source
Wikipedia: Emmy Noether
WikipediaPrincipal Result Of: Emmy Noether, Article text
Quote, Principal Result Of: Emmy Noether, Article text
In this paper Noether also introduced the Noether normalization lemma, showing that a finitely generated domain A over a field k has a set {x1, ..., xn} of algebraically independent elements such that A is integral over k[x1, ..., xn].
View the Source
Comments (0)
No comments yet. Be the first to share a thought.
Reader Challenges (0)
No disputes yet. Spotted an error or a better source? Open the first one.